如何在两个 NSDateComponents 之间获取 NSDateComponents?

问题描述

我有两个 NSDateComponents，我想要这两个之间的所有 NSDateComponents，我尝试了以下方法，

NSDateComponents *first = ...;NSDateComponents *second = ...;BOOL boolDone = 否;而 (!boolDone) {[数组添加对象:第一个]；第一天+=1；NSLog(@"%@",first);if([[第一个日期] 比较:[第二个日期]] == NSOrderedSame){boolDone = 是;}}NSLog(@"所有日期:%@",array);

在循环之后，它只打印我在first NSDateComponent 中的日期...！！怎么了?

这是一个需要理解的日志

2014-01-18 19:47:16.413 testCalendar[4274:a0b]

日历年:2014月份:1闰月:无天数:19

2014-01-18 19:47:16.415 testCalendar[4274:a0b]

日历年:2014月份:1闰月:无天数:20

2014-01-18 19:47:16.416 testCalendar[4274:a0b]

日历年:2014月份:1闰月:无天:21

2014-01-18 19:47:16.416 testCalendar[4274:a0b]

日历年:2014月份:1闰月:无天数:22

2014-01-18 19:47:16.417 testCalendar[4274:a0b]

日历年:2014月份:1闰月:无天数:23

2014-01-18 19:47:16.418 testCalendar[4274:a0b]

23-1-2014

23-1-2014

23-1-2014

23-1-2014

23-1-2014

您总是将相同的元素添加到数组中.数组只保存指针到它的元素，因此在循环结束时，它包含 n 个指向相同元素的指针对象first.改变

[array addObject:first];

到

[array addObject:[第一个副本]];

应该可以解决问题.

I've two NSDateComponents, I want all NSDateComponents in between those two, I've tried the following,

NSDateComponents *first = ...;
NSDateComponents *second = ...;

BOOL boolDone = NO;
while (!boolDone) {
    [array addObject:first];
    first.day+=1;
    NSLog(@"%@",first);

    if([[first date] compare:[second date]] == NSOrderedSame)
    {
        boolDone = YES;
    }
}

NSLog(@"All dates : %@",array);

After the loop, it just prints the date I've in first NSDateComponent...!! What's wrong?

Here's a log to understand

2014-01-18 19:47:16.413 testCalendar[4274:a0b]

Calendar Year: 2014
Month: 1
Leap month: no
Day: 19

2014-01-18 19:47:16.415 testCalendar[4274:a0b]

Calendar Year: 2014
Month: 1
Leap month: no
Day: 20

2014-01-18 19:47:16.416 testCalendar[4274:a0b]

Calendar Year: 2014
Month: 1
Leap month: no
Day: 21

2014-01-18 19:47:16.416 testCalendar[4274:a0b]

Calendar Year: 2014
Month: 1
Leap month: no
Day: 22

2014-01-18 19:47:16.417 testCalendar[4274:a0b]

Calendar Year: 2014
Month: 1
Leap month: no
Day: 23

2014-01-18 19:47:16.418 testCalendar[4274:a0b]

23-1-2014

23-1-2014

23-1-2014

23-1-2014

23-1-2014

You always add the same element to the array. The array just hold pointers to its elements, therefore at the end of the loop, it contains n pointers to the same object first. Changing

[array addObject:first];

to

[array addObject:[first copy]];

should solve the problem.