问题描述
以下是我的代码:
import math
print("Hey, lets solve Task 4 :)")
number1 = input("How many digits do you want to look at? ")
number2 = input("What would you like the digits to add up to? ")
if number1 == 1:
cow = range(0,10)
elif number1 == 2:
cow = range(10,100)
elif number1 == 3:
cow = range(100,1000)
elif number1 == 4:
cow = range(1000,10000)
elif number1 == 5:
cow = range(10000,100000)
elif number1 == 6:
cow = range(100000,1000000)
elif number1 == 7:
cow = range(1000000,10000000)
elif number1 == 8:
cow = range(10000000,100000000)
elif number1 == 9:
cow = range(100000000,1000000000)
elif number1 == 10:
cow = range(1000000000,10000000000)
number3 = cow[-1] + 1
n = 0
while n < number3:
number4 = list(cow[n])
n += 1
我希望创建一个循环,以便对于列表中的每个元素,它将被分解为它的每个字符。例如,假设数字137
在列表中,则它将转换为[1,3,7]
。然后我想把这些数字加在一起(我还没有开始,但我知道怎么做了)。
但是,我一直收到此错误消息:
TypeError: 'int' object is not iterable
我做错了什么?
推荐答案
您的线路有问题:
number4 = list(cow[n])
它尝试获取返回一个整数的cow[n]
,并使其成为一个列表。这不起作用,如下所示:
>>> a = 1
>>> list(a)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: 'int' object is not iterable
>>>
也许您打算将cow[n]
放在列表中:
number4 = [cow[n]]
请看下面的演示:
>>> a = 1
>>> [a]
[1]
>>>
另外,我想解决两件事:
您的While-语句末尾缺少:
。
这样使用input
被认为是非常危险的,因为它将其输入计算为真正的Python代码。这里最好使用raw_input
,然后使用int
将输入转换为整数。
要分割数字,然后按您希望的方式将其相加,我将首先将数字设置为字符串。然后,由于字符串是可迭代的,您可以使用sum
:
>>> a = 137
>>> a = str(a)
>>> # This way is more common and preferred
>>> sum(int(x) for x in a)
11
>>> # But this also works
>>> sum(map(int, a))
11
>>>