与if和is.na交叉突变

人气:540 发布:2022-10-16 标签: r dplyr na across

问题描述

我有下面列出的格式的数据,其中我需要处理的所有变量都是NA或变量的名称,我需要将Nas更改为0,将字符串更改为1。我尝试使用dplyr::across()ifelse(),但返回的都是1。我目前唯一有效的解决方案是分别对每个变量进行变异。

如何同时将多个变量中的所有NA更改为0,并将所有字符串更改为1?

library(dplyr)
color_names <- c("black", "grey", "white", "purple")

my_colors <- tribble(
  ~black, ~grey, ~white,  ~purple,
  NA,     "grey", NA,     "purple",
  NA,     NA,     "white", NA,
  "black",NA,     NA,      NA,
  NA,     "grey",  NA,     NA
)

my_colors %>%
  mutate(across(all_of(color_names), ~ifelse(is.na(cur_column()), 0, 1)))
#> # A tibble: 4 x 4
#>   black  grey white purple
#>   <dbl> <dbl> <dbl>  <dbl>
#> 1     1     1     1      1
#> 2     1     1     1      1
#> 3     1     1     1      1
#> 4     1     1     1      1

由reprex package(v0.3.0)于2021-01-13创建

推荐答案

我想您可以这样做:

library(tidyverse)
color_names <- c("black", "grey", "white", "purple")

my_colors <- tribble(
  ~black, ~grey, ~white,  ~purple,
  NA,     "grey", NA,     "purple",
  NA,     NA,     "white", NA,
  "black",NA,     NA,      NA,
  NA,     "grey",  NA,     NA
)

my_colors %>% 
  mutate(across(.cols = everything(),
                .fns = ~ ifelse(is.na(.x) == TRUE, 0, 1)))

# A tibble: 4 x 4
  black  grey white purple
  <dbl> <dbl> <dbl>  <dbl>
1     0     1     0      1
2     0     0     1      0
3     1     0     0      0
4     0     1     0      0

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