如何使用perl在代码中提供路径地址

问题描述

 使用  strict;   se警告;    my  $ file = register.txt;  ＃ 从文件中读取数据    my  $ data = slurp（ $ file ）;  ＃ 打印字符串数据   print   $ data ;   string  $ data  = FILE.ReadAllText（path）;   $ data  = data.Replace（  ， ，）;  file.WriteAllText（path，data）;   ＃ 我们只打印数据    print    $ data \ n;   close（ $ data ）; 

（这是我的代码，如何解决路径？ 我的给定数据，如20000行有转换

 arunav 1236  askjasi 25986  sdhfuis 26897  krotri 6598548 

我想要输出

 arunav，1236  askjasi，25986  sdhfuis，26897  krotri，6598548 

can请帮帮我

use strict;
 se warnings;

my $file=register.txt;
#read the data from file
 
 my $data= slurp($file);
#print the string data
print $data;

string $data = FILE.ReadAllText(path);
$data = data.Replace(" ",",");
file.WriteAllText(path,data);

#we will just print the data

print "$data\n";

close($data);

(this is my code in that howto address the path ? my given data like this 20000 lines are there to convert

arunav 1236
askjasi 25986
sdhfuis 26897
krotri  6598548

I want output

arunav,1236
askjasi,25986
sdhfuis,26897
krotri ,6598548

could please one help me